Compound Pulse

$1 invested for 1 year at 100% annual interest. Compounded once: $2. Compounded twice: $2.25. Compounded a hundred times: $2.7048. As the compounding frequency goes to infinity, the answer is exactly e.

The compounding staircase
A = (1 + r/n)nt
compounds n
12
final value
2.6130
e^r minus
0.1053
Approach to the limit
limn→∞ (1 + r/n)n = er
target e^r
2.7183
at n = 365
2.7146
at n = ∞
2.7183
rate r 1.00
compounds n 12
time t (years) 1.00
where e comes from
In 1683, Jacob Bernoulli was studying compound interest. With 100% annual rate compounded yearly, $1 becomes $2. Compounded twice yearly (50% twice), it becomes (1.5)² = $2.25. Compounded n times, it becomes (1 + 1/n)ⁿ. Bernoulli noticed this number had a limit as n grew — but he didn't compute it. Forty years later, Euler computed it to 23 digits and named it e.

The same logic applies at any rate: with continuous compounding at rate r, $1 grows to e^r in one year, and to e^(rt) in t years. Sliding the n-slider from 1 to 365 watches the discrete approach the continuous; the two converge faster for small r and slower for large r.